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1 point) Write an iterative method int sumofDigits(int x) that returns the sum of the digits of an integer. If x is 1234, the function should return 1 +2+3+4, that is, 10. If x is 345, the function should return 3+4+5 12. If x is 3, the function should return 3 If x is negative, ignore the minus sign. For example, -12 and 12 both return 3 (Hint: You can use x % 10 and x / 10 to get “the last digit” and “the rest of the digits,” respectively.) (1 point) Now, implement int sumofDigits(int x) using recursion -no explicit loop constructs (for, while) allowed! Show transcribed image text 1 point) Write an iterative method int sumofDigits(int x) that returns the sum of the digits of an integer. If x is 1234, the function should return 1 +2+3+4, that is, 10. If x is 345, the function should return 3+4+5 12. If x is 3, the function should return 3 If x is negative, ignore the minus sign. For example, -12 and 12 both return 3 (Hint: You can use x % 10 and x / 10 to get “the last digit” and “the rest of the digits,” respectively.) (1 point) Now, implement int sumofDigits(int x) using recursion -no explicit loop constructs (for, while) allowed!

## Expert Answer

**int sumOfDigits(int x) { if (x 0) { sum += (x % 10); x /= 10; } return sum;}**

**int sumOfDigits(int x) { if (x == 0) return 0; if (x < 0) x = -x; return sumOfDigits(x / 10) + (x % 10);}**using iteration using recur ston

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